Implement forgotten imperial measurement for Height field
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513adb71fd
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2 changed files with 5 additions and 2 deletions
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@ -24,7 +24,7 @@ namespace AuroraRecordGenerator
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record.AppendLine($"Clearance Level: {_targetRecord.Clearance.IfEmpty("Not Specified")}");
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record.AppendLine($"Employed As: {_targetRecord.EmployedAs.IfEmpty("Assistant")}");
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if (_targetRecord.CharHeight != null)
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record.AppendLine($"Height: {_targetRecord.CharHeight} cm");// ({Utility.CmToFeet(_targetRecord.CharHeight.Value)})
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record.AppendLine($"Height: {_targetRecord.CharHeight} cm ({Utility.CmToFeet(_targetRecord.CharHeight.Value)})");
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if (_targetRecord.Weight != null)
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record.AppendLine($"Weight: {_targetRecord.Weight} kg ({Utility.KgToLb(_targetRecord.Weight ?? 0)} lb)");
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@ -13,7 +13,10 @@ namespace AuroraRecordGenerator
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public static string CmToFeet(double cm)
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{
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return "0'0\"";
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var feet = Math.Floor(cm * 0.0328084);
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var inches = Math.Floor(cm * 0.39370079); // Isn't imperial a lovely system?
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inches -= feet * 12;
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return $"{feet}'{inches}\"";
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}
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/// <summary>
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